ACT Science Practice Question #1834 (Hard (560)) | Test Citadel
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ACT Science Difficulty: Hard (560)

Digital ACT Science Practice Question #1834

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The solubility product expression for the dissolution PbCl2(s) <=> Pb2+(aq) + 2 Cl-(aq) is: Experiment Context (Thermal Solubility of Lead(II) Chloride): Chemistry students dissolved excess PbCl2(s) in 100 mL of distilled water across five temperatures, filtering and titrating dissolved lead ions to compute Ksp: Table 27: - 10°C: Solubility = 0.68 g/100mL; Ksp = 6.2 x 10^-6 - 20°C: Solubility = 0.99 g/100mL; Ksp = 1.6 x 10^-5 - 40°C: Solubility = 1.45 g/100mL; Ksp = 4.8 x 10^-5 - 60°C: Solubility = 1.94 g/100mL; Ksp = 1.1 x 10^-4 - 80°C: Solubility = 2.50 g/100mL; Ksp = 2.4 x 10^-4
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Ksp = [Pb2+] * [Cl-]^2.

Masterclass Solution & Distractor Trap Analysis

Ksp = [Pb2+]^1 * [Cl-]^2. Pure solids (PbCl2) are omitted from equilibrium expressions....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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