ACT Science Practice Question #1833 (Hard (530)) | Test Citadel
TC
Test Citadel
ACT Science Difficulty: Hard (530)

Digital ACT Science Practice Question #1833

Test your problem-solving accuracy on this official-caliber item. Select an answer choice to check your reasoning instantly.

Based on Table 27, as water temperature increases from 10°C to 80°C, the dissolution of PbCl2(s) is: Experiment Context (Thermal Solubility of Lead(II) Chloride): Chemistry students dissolved excess PbCl2(s) in 100 mL of distilled water across five temperatures, filtering and titrating dissolved lead ions to compute Ksp: Table 27: - 10°C: Solubility = 0.68 g/100mL; Ksp = 6.2 x 10^-6 - 20°C: Solubility = 0.99 g/100mL; Ksp = 1.6 x 10^-5 - 40°C: Solubility = 1.45 g/100mL; Ksp = 4.8 x 10^-5 - 60°C: Solubility = 1.94 g/100mL; Ksp = 1.1 x 10^-4 - 80°C: Solubility = 2.50 g/100mL; Ksp = 2.4 x 10^-4
Select Your Answer:
Socratic AI Engine Step-by-Step Derivation
0ms Precomputed
⚡ 15-Second Desmos Speed Hack

Solubility increases with temperature -> Endothermic.

Masterclass Solution & Distractor Trap Analysis

Le Chatelier's Principle: if heating increases Ksp and solubility, the forward reaction absorbs heat (endothermic: Delta H > 0)....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

🔒 Citadel Pro Scholar Vault

Unlock Full Solution & 2,600+ Official Drills

Access detailed Socratic steps, trap breakdowns, authentic timed module simulations, and Desmos speed hacks for just $9.99/mo.

Socratic Assistant

Targeted hints without disclosing final solutions.

I am your Socratic tutor. Click one of the quick guidance buttons above or ask a specific question below about a formula or method.