ACT Science Practice Question #1866 (Hard (510)) | Test Citadel
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ACT Science Difficulty: Hard (510)

Digital ACT Science Practice Question #1866

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Based on Table 38, the gas evolved at the cathode is produced at twice the volume of the gas at the anode. The cathode gas is: Experiment Context (Stoichiometry of Aqueous Water Electrolysis): Students passed DC electrical current through an aqueous solution of 0.10 M Na2SO4 using platinum electrodes in a Hoffman apparatus, collecting evolved gases in calibrated burettes: Table 38: - 5 min: Cathode Gas Volume = 12.4 mL; Anode Gas Volume = 6.2 mL; Ratio (Cathode:Anode) = 2.00 - 10 min: Cathode Gas Volume = 24.8 mL; Anode Gas Volume = 12.4 mL; Ratio = 2.00 - 15 min: Cathode Gas Volume = 37.2 mL; Anode Gas Volume = 18.6 mL; Ratio = 2.00 - 20 min: Cathode Gas Volume = 49.6 mL; Anode Gas Volume = 24.8 mL; Ratio = 2.00
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2 H2O -> 2 H2 (cathode) + O2 (anode). Ratio = 2:1.

Masterclass Solution & Distractor Trap Analysis

Electrolysis of water produces 2 moles of H2 at the cathode for every 1 mole of O2 at the anode (2:1 volume ratio)....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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