ACT Science Practice Question #1775 (Hard (600)) | Test Citadel
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ACT Science Difficulty: Hard (600)

Digital ACT Science Practice Question #1775

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If one resistor burns out and becomes an open circuit in Circuit 2 (series) versus Circuit 4 (parallel): Experiment Context (Series and Parallel Resistor Circuits): An electronics laboratory tested circuits powered by an ideal 12.0 V DC power supply using three identical 6.0 ohm resistors (R1, R2, R3): Table 7: - Circuit 1 (Single resistor R1): Equivalent R = 6.0 ohms; Total Current = 2.00 A - Circuit 2 (Two resistors in series, R1 + R2): Equivalent R = 12.0 ohms; Total Current = 1.00 A - Circuit 3 (Three resistors in series, R1 + R2 + R3): Equivalent R = 18.0 ohms; Total Current = 0.67 A - Circuit 4 (Two resistors in parallel): Equivalent R = 3.0 ohms; Total Current = 4.00 A - Circuit 5 (Three resistors in parallel): Equivalent R = 2.0 ohms; Total Current = 6.00 A
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Socratic AI Engine Step-by-Step Derivation
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Series break stops all current; parallel branch continues.

Masterclass Solution & Distractor Trap Analysis

In series, an open breaks the entire loop (I=0). In parallel, the remaining branch still draws 12V / 6ohms = 2.0 A....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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