ACT Science Practice Question #1776 (Hard (510)) | Test Citadel
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ACT Science Difficulty: Hard (510)

Digital ACT Science Practice Question #1776

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Based on Table 8, during which time interval was the bacterial population dividing at its maximum exponential rate? Experiment Context (Bacterial Population Growth Phases): Microbiologists inoculated a nutrient broth with Escherichia coli at 37°C and sampled optical density at 600 nm (OD600, proportional to bacterial cell count) over 10 hours: Table 8: - Hour 0: OD600 = 0.05 (Lag phase) - Hour 1: OD600 = 0.06 (Lag phase) - Hour 2: OD600 = 0.18 (Log phase) - Hour 3: OD600 = 0.52 (Log phase) - Hour 4: OD600 = 1.48 (Log phase) - Hour 6: OD600 = 2.20 (Stationary phase) - Hour 8: OD600 = 2.22 (Stationary phase) - Hour 10: OD600 = 1.65 (Death phase)
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Steepest exponential rise occurs in log phase.

Masterclass Solution & Distractor Trap Analysis

OD600 jumped from 0.18 to 1.48 during Hours 2-4, indicating logarithmic growth....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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