ACT Science Practice Question #1774 (Hard (560)) | Test Citadel
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ACT Science Difficulty: Hard (560)

Digital ACT Science Practice Question #1774

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What is the total power dissipated by Circuit 5 (three 6.0 ohm resistors in parallel)? Experiment Context (Series and Parallel Resistor Circuits): An electronics laboratory tested circuits powered by an ideal 12.0 V DC power supply using three identical 6.0 ohm resistors (R1, R2, R3): Table 7: - Circuit 1 (Single resistor R1): Equivalent R = 6.0 ohms; Total Current = 2.00 A - Circuit 2 (Two resistors in series, R1 + R2): Equivalent R = 12.0 ohms; Total Current = 1.00 A - Circuit 3 (Three resistors in series, R1 + R2 + R3): Equivalent R = 18.0 ohms; Total Current = 0.67 A - Circuit 4 (Two resistors in parallel): Equivalent R = 3.0 ohms; Total Current = 4.00 A - Circuit 5 (Three resistors in parallel): Equivalent R = 2.0 ohms; Total Current = 6.00 A
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P = V * I = 12.0 * 6.0 = 72 W.

Masterclass Solution & Distractor Trap Analysis

P = V * I = 12.0 V * 6.00 A = 72.0 W (or V^2 / R = 144 / 2 = 72 W)....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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