ACT Science Practice Question #1504 (Medium (31)) | Test Citadel
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ACT Science Difficulty: Medium (31)

Digital ACT Science Practice Question #1504

Test your problem-solving accuracy on this official-caliber item. Select an answer choice to check your reasoning instantly.

Physicists irradiated a cesium metal plate with photons of various frequencies: - Frequency = 4.0 x 10^14 Hz: Kinetic energy of ejected electrons = 0.00 eV (no emission) - Frequency = 5.0 x 10^14 Hz: Kinetic energy = 0.14 eV - Frequency = 6.0 x 10^14 Hz: Kinetic energy = 0.55 eV - Frequency = 7.0 x 10^14 Hz: Kinetic energy = 0.96 eV The threshold frequency required to eject electrons from cesium is approximately:
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Threshold is where KE transitions from 0 to positive: between 4.0 and 5.0 x 10^14 Hz.

Masterclass Solution & Distractor Trap Analysis

At 4.0 x 10^14 Hz no electrons are ejected; at 5.0 x 10^14 Hz emission occurs with 0.14 eV. The threshold lies between these two values....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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