ACT Science Practice Question #1797 (Hard (530)) | Test Citadel
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Digital ACT Science Practice Question #1797

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Based on Table 15, the threshold frequency (f_0) required to eject photoelectrons from potassium lies between: Experiment Context (Photoelectric Work Function of Potassium): Monochromatic light of varying frequencies was shone onto a clean potassium metal cathode in a vacuum phototube, and maximum kinetic energy of emitted photoelectrons was measured: Table 15: - Red Light (4.5 x 10^14 Hz): Photoelectrons emitted = None; Max KE = 0.00 eV - Yellow Light (5.2 x 10^14 Hz): Photoelectrons emitted = None; Max KE = 0.00 eV - Green Light (5.8 x 10^14 Hz): Photoelectrons emitted = Yes; Max KE = 0.12 eV - Blue Light (6.5 x 10^14 Hz): Photoelectrons emitted = Yes; Max KE = 0.41 eV - Violet Light (7.5 x 10^14 Hz): Photoelectrons emitted = Yes; Max KE = 0.82 eV
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Threshold is where emission first becomes non-zero.

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Emission begins between Yellow (5.2, no emission) and Green (5.8, emission at 0.12 eV)....

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