ACT Math Practice Question #1471 (Medium (32)) | Test Citadel
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ACT Math Difficulty: Medium (32)

Digital ACT Math Practice Question #1471

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What is the maximum value of the function f(x) = -x^2 + 6x - 2 on the closed interval [0, 5]?
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Vertex is at x = 3. f(3) = -9 + 18 - 2 = 7.

Masterclass Solution & Distractor Trap Analysis

The parabola opens downward. The vertex occurs at x = -b/(2a) = -6 / (2*-1) = 3, which lies inside [0, 5]. Evaluating at vertex: f(3) = -(3)^2 + 6(3) - 2 = -9 + 18 - 2 = 7. Evaluating endpoints: f(0) = -2, f(5) = -25 + 30 - 2 = 3. The maxim...

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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