ACT Math Practice Question #1464 (Hard (33)) | Test Citadel
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ACT Math Difficulty: Hard (33)

Digital ACT Math Practice Question #1464

Test your problem-solving accuracy on this official-caliber item. Select an answer choice to check your reasoning instantly.

A committee of 3 people is to be selected from a group of 7 candidates: Alice, Bob, and 5 others. If Alice and Bob refuse to serve on the committee together, how many different 3-person committees are possible?
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Total = C(7, 3) = 35. Both together = 5. Allowed = 35 - 5 = 30.

Masterclass Solution & Distractor Trap Analysis

Total possible 3-person committees from 7 = C(7, 3) = (7*6*5)/(3*2*1) = 35. Committees containing BOTH Alice and Bob require choosing 1 remaining person from the other 5: C(5, 1) = 5. Committees where they do NOT serve together = 35 - 5 = 3...

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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