Digital ACT Math Practice Question #1284
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$r = \sqrt{(d/2)^2 + (e/2)^2 - f} = \sqrt{(-3)^2 + (4)^2 - (-11)} = \sqrt{9 + 16 + 11} = \sqrt{36} = 6$.
Complete the square for $x$ and $y$: $(x^2 - 6x + 9) + (y^2 + 8y + 16) = 11 + 9 + 16$ $(x - 3)^2 + (y + 4)^2 = 36$. The standard equation of a circle is $(x - h)^2 + (y - k)^2 = r^2$. Here, $r^2 = 36$, so the radius is $r = \sqrt{36} = 6$....
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