ACT Math Practice Question #1455 (Medium (32)) | Test Citadel
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ACT Math Difficulty: Medium (32)

Digital ACT Math Practice Question #1455

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If x = 2 is a root of the polynomial P(x) = x^3 - 4x^2 + x + 6, what are the other two roots?
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Quotient = x^2 - 2x - 3 = (x - 3)(x + 1) = 0 -> roots are 3 and -1.

Masterclass Solution & Distractor Trap Analysis

Divide P(x) by (x - 2): quotient is x^2 - 2x - 3. Factoring x^2 - 2x - 3 = (x - 3)(x + 1) = 0 gives roots x = 3 and x = -1....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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