ACT Science Practice Question #1224 (Medium (31)) | Test Citadel
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ACT Science Difficulty: Medium (31)

Digital ACT Science Practice Question #1224

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A chemistry student measures the pH of four aqueous solutions at $25^\circ\text{C}$: • Solution 1: $[\text{H}^+] = 1.0 \times 10^{-3}\text{ M}$ • Solution 2: $[\text{OH}^-] = 1.0 \times 10^{-4}\text{ M}$ • Solution 3: $[\text{H}^+] = 1.0 \times 10^{-8}\text{ M}$ • Solution 4: $[\text{OH}^-] = 1.0 \times 10^{-11}\text{ M}$ Recall that $\text{pH} = -\log_{10}[\text{H}^+]$ and $[\text{H}^+][\text{OH}^-] = 1.0 \times 10^{-14}$. Which solution is the most acidic?
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Most acidic = lowest pH = highest $[\text{H}^+]$. Solution 1 has $[\text{H}^+] = 10^{-3}$ ($pH = 3$).

Masterclass Solution & Distractor Trap Analysis

Calculate pH for each solution: • Solution 1: $\text{pH} = -\log(10^{-3}) = 3.0$ • Solution 2: $[\text{H}^+] = 10^{-14} / 10^{-4} = 10^{-10} \implies \text{pH} = 10.0$ • Solution 3: $\text{pH} = -\log(10^{-8}) = 8.0$ • Solution 4: $[\text{H...

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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