Digital ACT Math Practice Question #1207
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Skip finding $a_1$! Directly add $(25 - 10) = 15$ common differences to $a_{10}$: $49 + 15(5) = 49 + 75 = 124$.
The $n^{\text{th}}$ term is $a_n = a_1 + (n - 1)d$. The difference between the $10^{\text{th}}$ and $4^{\text{th}}$ terms is: $$a_{10} - a_4 = (10 - 4)d \implies 49 - 19 = 6d \implies 30 = 6d \implies d = 5.$$ To find the $25^{\text{th}}$ t...
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