ACT Math Practice Question #1288 (Medium (29)) | Test Citadel
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ACT Math Difficulty: Medium (29)

Digital ACT Math Practice Question #1288

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A fair six-sided die is rolled three times. What is the probability that the numbers rolled strictly increase (that is, the second roll is greater than the first, and the third roll is greater than the second)?
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Combinations: $\binom{6}{3} / 6^3 = 20 / 216 = 5 / 54$.

Masterclass Solution & Distractor Trap Analysis

Total possible outcomes from three rolls of a 6-sided die: $6^3 = 216$. Any set of $3$ distinct numbers from $\{1, 2, 3, 4, 5, 6\}$ can be arranged in strictly increasing order in exactly ONE way. The number of ways to choose $3$ distinct n...

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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