Digital SAT Math Practice Question #961
Test your problem-solving accuracy on this official-caliber item. Select an answer choice to check your reasoning instantly.
Complete the square for the \( x \) and \( y \) terms to identify the center \( (h, k) \) of the circle. Then observe the relationship between the center and the given point of tangency.
Desmos Shortcut: Type the original circle equation directly into Desmos: \( x^2 + y^2 - 8x + 6y - 11 = 0 \). Desmos graphs implicit relations effortlessly! Plot the point \( (4, 3) \) to immediately see that the tangent line is a flat horizontal line.
First, complete the square to write the circle in standard form \( (x - h)^2 + (y - k)^2 = r^2 \): \[ (x - 4)^2 + (y - -3)^2 = 36 \] The center of the circle is \( (4, -3) \) and the radius is \( 6 \). The point of tangency is \( P(4, 3) \)...
Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...
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