ACT Math Practice Question #852 (Hard (36)) | Test Citadel
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ACT Math Difficulty: Hard (36)

Digital ACT Math Practice Question #852

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Matrices \( A \) and \( B \) are given by: \[ A = \begin{pmatrix} 4 & -3 \\ 2 & k \end{pmatrix}, \quad B = \begin{pmatrix} 6 & 1 \\ -2 & 3 \end{pmatrix} \] If the determinant of \( A \) is equal to twice the determinant of \( B \), what is the value of \( k \)?
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Socratic AI Engine Step-by-Step Derivation
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Tactical Insight (Hint 1)

Recall the 2x2 determinant formula: \( \det\begin{pmatrix} a & b \\ c & d \end{pmatrix} = ad - bc \). Be extremely careful with negative signs when subtracting \( bc \).

Elimination Framework (Hint 2)

Tactical Shortcut: Calculate \( \det(B) \) first. Once you have \( \det(B) = 20 \), double it to 40. Then write \( 4k - (-6) = 40 \) and solve for \( k \).

Masterclass Solution & Distractor Trap Analysis

Step 1: Calculate the determinant of matrix \( B \): \[ \det(B) = (6)(3) - (1)(-2) = 18 + 2 = 20 \] Step 2: State the condition: \( \det(A) = 2 \cdot \det(B) = 2(20) = 40 \). Step 3: Calculate \( \det(A) \) in terms of \( k \): \[ \det(A) =...

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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