SAT Math Practice Question #708 (Hard (800)) | Test Citadel
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SAT Math Difficulty: Hard (800)

Digital SAT Math Practice Question #708

Test your problem-solving accuracy on this official-caliber item. Select an answer choice to check your reasoning instantly.

In the \( xy \)-plane, a circle with radius \( r \) is centered at the origin. A line intersects the circle at points \( P \) and \( Q \). The coordinates of \( P \) are \( \left(-\frac{1}{2}r, \frac{\sqrt{3}}{2}r\right) \) and the coordinates of \( Q \) are \( \left(\frac{\sqrt{2}}{2}r, -\frac{\sqrt{2}}{2}r\right) \). What is the shortest distance along the circle (the minor arc length) between points \( P \) and \( Q \), in terms of \( r \)?
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Socratic AI Engine Step-by-Step Derivation
0ms Precomputed
Tactical Insight (Hint 1)

Recall the standard circle equation: \( (x - h)^2 + (y - k)^2 = r^2 \). Complete the square if the equation is expanded.

Elimination Framework (Hint 2)

Desmos Tactical Shortcut: Plot the left-hand side and right-hand side as separate equations (e.g. \( y_1 = f(x) \) and \( y_2 = g(x) \)). Click the intersection points directly to read exact coordinates.

Masterclass Solution & Distractor Trap Analysis

This problem is a masterful blend of unit circle trigonometry and geometric arc length. It looks intimidating, but translating the coordinates into angles unravels it completely. Because the circle is centered at the origin with radius \( r...

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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