SAT Math Practice Question #426 (Hard (800)) | Test Citadel
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SAT Math Difficulty: Hard (800)

Digital SAT Math Practice Question #426

Test your problem-solving accuracy on this official-caliber item. Select an answer choice to check your reasoning instantly.

The graph of the equation \( y = ax^2 + bx + c \) in the \( xy \)-plane, where \( a \), \( b \), and \( c \) are constants and \( a > 0 \), has its vertex at \( (3, -4) \). A line with the equation \( y = -2x + k \), where \( k \) is a constant, intersects the parabola at exactly one point. If the \( x \)-coordinate of the point of intersection is \( 2 \), what is the value of \( k \)?
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Socratic AI Engine Step-by-Step Derivation
0ms Precomputed
Tactical Insight (Hint 1)

Identify the quadratic form: consider converting to vertex form \( y = a(x-h)^2 + k \) or using \( x = - rac{b}{2a} \) to find the line of symmetry.

Elimination Framework (Hint 2)

Desmos Tactical Shortcut: Plot the left-hand side and right-hand side as separate equations (e.g. \( y_1 = f(x) \) and \( y_2 = g(x) \)). Click the intersection points directly to read exact coordinates.

Masterclass Solution & Distractor Trap Analysis

This requires marrying vertex form with systems of equations and the concept of tangency. Let's walk through it step-by-step. Step 1: Construct the parabola's equation. Since we know the vertex is \( (3, -4) \), we can immediately use verte...

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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