Digital SAT Math Practice Question #2376
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Square both sides: $(x - 4)^2 = x + 2 \implies x^2 - 8x + 16 = x + 2 \implies x^2 - 9x + 14 = 0 \implies (x - 7)(x - 2) = 0$. For $x = 2$, $2 - 4 = -2 \ne \sqrt{4}$ (extraneous). For $x = 7$, $7 - 4 = 3 = \sqrt{9}$ (valid). Thus $x = 7$....
Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...
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