SAT Math Practice Question #2352 (Medium) | Test Citadel
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SAT Math Difficulty: Medium

Digital SAT Math Practice Question #2352

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If $\frac{x^2 - c}{x - 4} = x + 4$ for all $x \ne 4$, what is the value of $c$?
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Masterclass Solution & Distractor Trap Analysis

$(x - 4)(x + 4) = x^2 - 16$. Comparing with $x^2 - c$, we have $c = 16$....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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