SAT Math Practice Question #2264 (Medium) | Test Citadel
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SAT Math Difficulty: Medium

Digital SAT Math Practice Question #2264

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If $f(x) = x^2 - 6x + c$ and the minimum value of $f(x)$ is $-4$, what is the value of $c$?
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Masterclass Solution & Distractor Trap Analysis

Vertex $x$-coordinate is $x = -(-6)/2 = 3$. Minimum value: $f(3) = 3^2 - 6(3) + c = 9 - 18 + c = -9 + c$. Set equal to $-4$: $-9 + c = -4 \implies c = 5$....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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