ACT Math Practice Question #2128 (Hard) | Test Citadel
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ACT Math Difficulty: Hard

Digital ACT Math Practice Question #2128

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A surveyor stands 100 feet from the base of a vertical tower on level ground. The angle of elevation from the ground to the top of the tower is $37^\circ$. If $\tan 37^\circ \approx 0.75$, what is the approximate height of the tower, in feet?
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Height = $\text{adjacent} \times \tan(\theta) = 100 \times 0.75 = 75$.

Masterclass Solution & Distractor Trap Analysis

From the right triangle: $\tan 37^\circ = \frac{\text{height}}{100} \implies \text{height} = 100 \times \tan 37^\circ \approx 100 \times 0.75 = 75$ feet....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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