ACT Math Practice Question #2118 (Medium) | Test Citadel
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ACT Math Difficulty: Medium

Digital ACT Math Practice Question #2118

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What is the period of the trigonometric function $f(x) = 3\sin(4x - \pi) + 2$?
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Period of sine/cosine is always $2\pi / B$. $2\pi / 4 = \pi/2$.

Masterclass Solution & Distractor Trap Analysis

For a sine function $y = A\sin(Bx - C) + D$, the period is given by $T = \frac{2\pi}{|B|}$. Here $B = 4$, so the period is $\frac{2\pi}{4} = \frac{\pi}{2}$....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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