Digital ACT Math Practice Question #2104
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Cube space diagonal is always $s\sqrt{3}$. $s = \sqrt{150/6} = 5 \implies 5\sqrt{3}$.
A cube has 6 faces of area $s^2$. $6s^2 = 150 \implies s^2 = 25 \implies s = 5$. The interior space diagonal of a cube of side $s$ is $s\sqrt{3} = 5\sqrt{3}$....
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