Digital ACT Math Practice Question #2101
Test your problem-solving accuracy on this official-caliber item. Select an answer choice to check your reasoning instantly.
Dimensional scaling: Length scales by $k$, Area by $k^2$, Volume by $k^3$. $2^3 = 8$.
Volume of a sphere is $V = \frac{4}{3}\pi r^3$. If $r$ is replaced by $2r$, the new volume is $V' = \frac{4}{3}\pi (2r)^3 = 8 \left(\frac{4}{3}\pi r^3\right) = 8V$....
Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...
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