ACT Math Practice Question #2099 (Hard) | Test Citadel
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ACT Math Difficulty: Hard

Digital ACT Math Practice Question #2099

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A rectangular box has length 4 inches, width 3 inches, and height 12 inches. What is the length, in inches, of the longest interior diagonal that connects two opposite vertices of the box?
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3D Pythagorean Theorem: $d = \sqrt{l^2 + w^2 + h^2} = \sqrt{16+9+144} = \sqrt{169} = 13$.

Masterclass Solution & Distractor Trap Analysis

The length of the interior space diagonal is given by $d = \sqrt{l^2 + w^2 + h^2} = \sqrt{4^2 + 3^2 + 12^2} = \sqrt{16 + 9 + 144} = \sqrt{169} = 13$....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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