ACT Math Practice Question #2097 (Hard) | Test Citadel
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ACT Math Difficulty: Hard

Digital ACT Math Practice Question #2097

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A bag contains 5 red marbles, 4 blue marbles, and 3 green marbles. If 3 marbles are drawn at random without replacement, what is the probability that all 3 are red?
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Multiply conditional probabilities: $(5/12) \times (4/11) \times (3/10) = 1/22$.

Masterclass Solution & Distractor Trap Analysis

Total marbles = $5 + 4 + 3 = 12$. The probability of drawing 3 red marbles sequentially without replacement is $\frac{5}{12} \times \frac{4}{11} \times \frac{3}{10} = \frac{60}{1320} = \frac{1}{22}$. Equivalently, $\frac{_5C_3}{_{12}C_3} = ...

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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