ACT Math Practice Question #2070 (Hard (610)) | Test Citadel
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ACT Math Difficulty: Hard (610)

Digital ACT Math Practice Question #2070

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An ellipse has the equation (x - 2)^2 / 289 + (y + 1)^2 / 64 = 1. What is the distance from the center of the ellipse to each of its foci?
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c = sqrt(a^2 - b^2) = sqrt(289 - 64) = 15.

Masterclass Solution & Distractor Trap Analysis

In an ellipse, focal distance c satisfies c^2 = a^2 - b^2 = 289 - 64 = 225. Thus c = sqrt(225) = 15....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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