ACT Science Practice Question #1854 (Hard (510)) | Test Citadel
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ACT Science Difficulty: Hard (510)

Digital ACT Science Practice Question #1854

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Based on Table 34, doubling the slit separation d at a constant screen distance (from 0.10 mm to 0.20 mm) causes the fringe spacing y to: Experiment Context (Interference Fringe Spacing of Laser Light): Students directed a 632.8 nm helium-neon red laser through a double-slit aperture onto a screen 2.0 m away, measuring fringe spacing (y) between adjacent bright fringes: Table 34: - Slit Separation d = 0.10 mm: Screen Distance L = 2.0 m; Fringe Spacing y = 12.7 mm - Slit Separation d = 0.20 mm: Screen Distance L = 2.0 m; Fringe Spacing y = 6.3 mm - Slit Separation d = 0.40 mm: Screen Distance L = 2.0 m; Fringe Spacing y = 3.2 mm - Slit Separation d = 0.20 mm: Screen Distance L = 4.0 m; Fringe Spacing y = 12.7 mm
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Fringe spacing is inversely proportional to slit width d.

Masterclass Solution & Distractor Trap Analysis

y = (lambda * L) / d. Fringe spacing is inversely proportional to slit separation d....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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