ACT Science Practice Question #1764 (Hard (530)) | Test Citadel
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ACT Science Difficulty: Hard (530)

Digital ACT Science Practice Question #1764

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Based on Table 4, the equivalence point of this titration occurred at: Experiment Context (Potentiometric Titration of Weak Acid): A 25.0 mL sample of 0.10 M acetic acid (CH3COOH) was titrated with 0.10 M NaOH. The pH was monitored using a glass electrode: Table 4: - 0.0 mL NaOH: pH = 2.87 - 6.25 mL NaOH: pH = 4.28 - 12.5 mL NaOH: pH = 4.76 - 20.0 mL NaOH: pH = 5.35 - 25.0 mL NaOH: pH = 8.72 - 30.0 mL NaOH: pH = 11.96
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Socratic AI Engine Step-by-Step Derivation
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Steepest pH jump identifies the equivalence point.

Masterclass Solution & Distractor Trap Analysis

Equivalence point occurs where stoichiometry matches (25.0 mL) with a dramatic pH jump to 8.72....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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