ACT Science Practice Question #1761 (Hard (550)) | Test Citadel
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ACT Science Difficulty: Hard (550)

Digital ACT Science Practice Question #1761

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Based on Table 3, doubling the release height h from 0.20 m to 0.40 m causes the launch speed to: Experiment Context (Incline Ramp Velocity and Range): A steel sphere (mass = 0.05 kg) was released from rest at various heights (h) above a smooth table, rolling down a ramp and launching horizontally from a table height of 1.0 m: Table 3: - h = 0.10 m: Launch speed = 1.4 m/s; Horizontal range = 0.63 m - h = 0.20 m: Launch speed = 2.0 m/s; Horizontal range = 0.90 m - h = 0.40 m: Launch speed = 2.8 m/s; Horizontal range = 1.27 m - h = 0.80 m: Launch speed = 4.0 m/s; Horizontal range = 1.81 m
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2.8 / 2.0 = 1.4 = sqrt(2).

Masterclass Solution & Distractor Trap Analysis

2.8 / 2.0 = 1.4. By conservation of energy, v = sqrt(2gh)....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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