Digital SAT Math Practice Question #1639
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Denominator = 0: x^2 - 9 = 0 -> x = ±3.
Vertical asymptotes occur where the denominator equals zero and the numerator is nonzero. Setting \(x^2 - 9 = 0\) yields \((x - 3)(x + 3) = 0\), so \(x = 3\) and \(x = -3\). Neither zeroes the numerator \(x + 4\), so both are vertical asymp...
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