Digital SAT Math Practice Question #1635
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b^2 - 4ac = 0 -> 64 - 8c = 0 -> c = 8.
A quadratic equation has exactly one real solution when its discriminant equals zero: \(b^2 - 4ac = 0\). Here \(a = 2, b = -8\), so \((-8)^2 - 4(2)(c) = 0 \implies 64 - 8c = 0 \implies 8c = 64 \implies c = 8\)....
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