Digital ACT Math Practice Question #1621
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Independent combinations multiply: binom(6,2) = 15, binom(5,2) = 10. 15 * 10 = 150.
Number of ways to choose 2 chemists from 6: \(\binom{6}{2} = \frac{6 \times 5}{2 \times 1} = 15\). Number of ways to choose 2 physicists from 5: \(\binom{5}{2} = \frac{5 \times 4}{2 \times 1} = 10\). Total combinations = \(15 \times 10 = 15...
Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...
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