ACT Science Practice Question #1541 (Medium (29)) | Test Citadel
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ACT Science Difficulty: Medium (29)

Digital ACT Science Practice Question #1541

Test your problem-solving accuracy on this official-caliber item. Select an answer choice to check your reasoning instantly.

A 1.0 kg mass oscillates on a vertical spring (k = 100 N/m): - At top of swing (maximum displacement): Kinetic energy = 0 J, Potential energy = 2.0 J - At equilibrium position: Kinetic energy = 2.0 J, Potential energy = 0 J - At bottom of swing: Kinetic energy = 0 J, Potential energy = 2.0 J Throughout the oscillation, total mechanical energy (KE + PE):
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Total energy = 0 + 2.0 = 2.0 J at every point.

Masterclass Solution & Distractor Trap Analysis

KE + PE = 2.0 J at all positions, verifying the law of conservation of mechanical energy in the absence of friction....

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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