Digital ACT Math Practice Question #1320
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Recognize standard Pythagorean triples: $9-40-41$. The modulus is instantly $41$.
The modulus of a complex number $z = a + bi$ is defined as $|z| = \sqrt{a^2 + b^2}$. $$|z| = \sqrt{9^2 + (-40)^2} = \sqrt{81 + 1600} = \sqrt{1681} = 41.$$...
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