Digital ACT Math Practice Question #1263
Test your problem-solving accuracy on this official-caliber item. Select an answer choice to check your reasoning instantly.
Because $\cos(60^\circ) = 1/2$, the formula simplifies immediately to $c = \sqrt{a^2 + b^2 - ab} = \sqrt{36 + 100 - 60} = \sqrt{76}$.
Apply the Law of Cosines: $c^2 = a^2 + b^2 - 2ab\cos(C)$. Substitute $a = 6$, $b = 10$, and $C = 60^\circ$: $$c^2 = 6^2 + 10^2 - 2(6)(10)\cos(60^\circ) = 36 + 100 - 2(60)(0.5) = 136 - 60 = 76.$$ Thus, $c = \sqrt{76}\text{ feet}$....
Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...
Unlock Full Solution & 2,600+ Official Drills
Access detailed Socratic steps, trap breakdowns, authentic timed module simulations, and Desmos speed hacks for just $9.99/mo.
For what value of k does the matrix [[3, 9], [k, 15]] have a determinant equal to 0?...
Working alone at a constant rate, pump A can empty a water reservoir in 6 hours, while pump B can empty the same reservo...
For what value of k does the matrix [[6, 18], [4, k]] have a determinant equal to 0?...
If angle x is in the first quadrant and sin(x) = 7/25, what is the value of cos(x)?...