Digital ACT Math Practice Question #1210
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Radius is $\sqrt{36} = 6$. Circumference is $2\pi r = 12\pi$.
The standard equation of a circle is $(x - h)^2 + (y - k)^2 = r^2$. Here, $r^2 = 36$, so the radius is $r = \sqrt{36} = 6$. The circumference of a circle is $C = 2\pi r = 2\pi(6) = 12\pi$....
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