SAT Math Practice Question #1174 (Hard (800)) | Test Citadel
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SAT Math Difficulty: Hard (800)

Digital SAT Math Practice Question #1174

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>r >h
Note: Figure not drawn to scale.
A company plans to paint the exterior of a grain silo, which is shaped like a cylinder topped with a hemisphere, as shown in the figure. The cylindrical part has a radius of \(r = 10\) feet and a height of \(h = 30\) feet. The hemispherical top has the same radius as the cylinder. If the base of the silo rests on the ground and will not be painted, what is the total exterior surface area, in square feet, that will be painted?
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Socratic AI Engine Step-by-Step Derivation
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Tactical Insight (Hint 1)

What are the individual geometric shapes that make up the exterior surface to be painted? Remember to exclude any surfaces that are on the ground or covered by another part of the silo.

Elimination Framework (Hint 2)

Recall the formulas for the lateral surface area of a cylinder and the curved surface area of a hemisphere. Be careful not to include the flat base of the hemisphere or the circular base of the cylinder that is on the ground.

⚡ 15-Second Desmos Speed Hack

Quickly identify the two components needing paint: the cylinder's side and the hemisphere's dome. Recall their formulas: \(2\pi rh\) for the cylinder's lateral surface and \(2\pi r^2\) for the hemisphere's curved surface. Substitute the given values \(r=10\) and \(h=30\): \(2\pi(10)(30) = 600\pi\) and \(2\pi(10)^2 = 200\pi\). Sum these two values: \(600\pi + 200\pi = 800\pi\). Scan the options for \(800\pi\). This direct calculation is efficient and less prone to error than trying to eliminate options without calculation.

Masterclass Solution & Distractor Trap Analysis

To find the total exterior surface area that will be painted, we need to calculate the sum of the lateral surface area of the cylindrical part and the curved surface area of the hemispherical top. The base of the silo rests on the ground an...

Distractor Analysis: Trap choice eliminates careless test-takers who confuse roots with coordinates...

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